Network Delay Time: the idea to remember.
Find how long a signal from one node takes to reach every node in a weighted directed graph, or return minus one.
The core insight
Initialize source distance to zero and repeatedly relax every directed edge.
Why it works
After enough passes, every shortest simple path has been considered; the latest finite arrival determines the total delay.
The mistake to avoid
Check reachability before adding an edge weight; an unreachable node makes the final answer minus one.
Commented Java solution
Use java.util.* imports and a surrounding solution class. Tree snippets assume the standard TreeNode definition; linked lists use ListNode and Clone Graph uses a Node with val and neighbors; Copy Random List uses Node with val, next and random. Read the input assumptions above.
// Java reference adapted from neetcode-gh/leetcode (MIT).
// Initialize source distance to zero and repeatedly relax every directed edge.
public int networkDelayTime(int[][] times, int n, int k) {
int[] paths = new int[n];
Arrays.fill(paths, Integer.MAX_VALUE);
paths[k - 1] = 0;
for (int i = 0; i < n; i++) {
int[] temp = new int[n];
temp = Arrays.copyOf(paths, paths.length);
for (int j = 0; j < times.length; j++) {
int src = times[j][0];
int tgt = times[j][1];
int time = times[j][2];
if (
temp[src - 1] != Integer.MAX_VALUE &&
temp[src - 1] + time < temp[tgt - 1]
) {
temp[tgt - 1] = temp[src - 1] + time;
}
}
paths = temp;
}
int result = Integer.MIN_VALUE;
for (int i = 0; i < n; i++) {
if (paths[i] == Integer.MAX_VALUE) {
return -1;
}
result = Math.max(result, paths[i]);
}
return result;
}Java reference adapted from neetcode-gh/leetcode · MIT license
Make the next connection
Independent revision notes with credited Java references. Not affiliated with LeetCode or the source sheets.