Valid Parenthesis String: the idea to remember.
Determine whether a parentheses string can be balanced when each star may represent open, close, or empty.
The core insight
Maintain the minimum and maximum possible unmatched opens after each prefix.
Why it works
The interval represents every feasible balance: star widens it, closing shifts it down, and negative maximum means no valid interpretation remains.
The mistake to avoid
Clamp the minimum to zero, but reject a negative maximum immediately. A final minimum of zero is required.
Commented Java solution
Use java.util.* imports and a surrounding solution class. Tree snippets assume the standard TreeNode definition; linked lists use ListNode and Clone Graph uses a Node with val and neighbors; Copy Random List uses Node with val, next and random. Read the input assumptions above.
// Java reference adapted from neetcode-gh/leetcode (MIT).
// Maintain the minimum and maximum possible unmatched opens after each prefix.
public boolean checkValidString(String s) {
int low = 0, high = 0;
for (int i = 0; i < s.length(); i++) {
if (s.charAt(i) == '(') {
low++;
high++;
} else if (s.charAt(i) == ')') {
if (low > 0) {
low--;
}
high--;
} else {
if (low > 0) {
low--;
}
high++;
}
if (high < 0) {
return false;
}
}
return low == 0;
}Java reference adapted from neetcode-gh/leetcode · MIT license
Make the next connection
Independent revision notes with credited Java references. Not affiliated with LeetCode or the source sheets.